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Rate of Change of a Volume Function
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All of the following statements regarding the rate of change of water volume in a pool described by $$V(t)=8*t^2-32*t+4$$ are true except:

t (hours) $$dV/dt$$ (gallons/hour)
1 -16
2 0
3 16
A

The derivative of the volume function represents the rate at which the pool’s water volume changes over time.

B

At $$t=2$$, substituting into the derivative yields $$V'(2)=16*2-32=0$$, correctly showing no instantaneous change in volume.

C

For $$V(t)=8*t^2-32*t+4$$, application of the power rule yields $$V'(t)=16*t-32$$.

D

Differentiating $$V(t)=8*t^2-32*t+4$$ gives $$V'(t)=16*t+32$$, indicating the rate of volume change increases linearly.

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