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AP Calculus BC/Unit 7: Differential Equations
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Particular Solution to a Differential Equation

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If dydx=y2\displaystyle\frac{dy}{dx} = y^2, and if y=12y = \frac{1}{2} when x=0x = 0, then y=y =

A

22x\frac{2}{2-x}

B

12+x\frac{1}{2+x}

C

1x2\frac{1}{x-2}

D

12x\frac{1}{2-x}

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