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AP Calculus BC/Unit 1: Limits and Continuity
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Identifying Removable Discontinuities

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Which of the following is an example of a function with a removable discontinuity? Remember that a removable discontinuity occurs when the function is undefined at a point even though the limit exists there, and the discontinuity can be “removed” by redefining the function at that point.

A

The function k(x)=(x−2)∗(x+3)(x−2)2k(x)=\frac{(x-2)*(x+3)}{(x-2)^2}, where cancellation is incomplete and the discontinuity at x=2x=2 remains essential.

B

The function h(x)=∣x−2∣h(x)=|x-2|, which is continuous everywhere but not differentiable at x=2x=2 due to a sharp corner.

C

The function f(x)={(x−2)∗(x+3)x−2x≠25x=2f(x)=\begin{cases} \frac{(x-2)*(x+3)}{x-2} & x\neq 2 \\ 5 & x=2 \end{cases}, which simplifies to x+3x+3 for all x except at x=2x=2 and can be redefined to be continuous.

D

The function g(x)=x+1x−2g(x)=\frac{x+1}{x-2}, which has a vertical asymptote at x=2x=2 and cannot be redefined to remove the discontinuity.

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