What is the value of the following limit? limx→∞ln(5e3x+2e7x)4x\displaystyle \lim_{x \to \infty} \frac{\ln \left( 5e^{3x} + 2e^{7x} \right)}{4x}x→∞lim4xln(5e3x+2e7x)
94 \frac{9}{4} 49
54\frac{5}{4} 45
74 \frac{7}{4} 47
34 \frac{3}{4} 43
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