Sum of a Geometric Series
$$\displaystyle\sum_{n=3}^{\infty} \frac{6^{n-2}}{8^n}$$ is
A
$$\displaystyle\frac{9}{64}$$
B
$$\text{divergent}$$
C
$$\displaystyle\frac{27}{256}$$
D
$$\displaystyle\frac{3}{64}$$
$$\displaystyle\sum_{n=3}^{\infty} \frac{6^{n-2}}{8^n}$$ is
$$\displaystyle\frac{9}{64}$$
$$\text{divergent}$$
$$\displaystyle\frac{27}{256}$$
$$\displaystyle\frac{3}{64}$$