APFIVE Radical Equation With Absolute Value
Solve for x:
$$\sqrt{x^2+6*x+9} + \sqrt{x^2-4} = 7.$$
(Note: Recognize that $$\sqrt{x^2+6*x+9} = |x+3|$$ and use the domain restrictions.)
A
$$x = -2.5$$
B
$$x = 3.5$$
C
$$x = 2.5$$
D
$$x = 4$$
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