∑n=3∞6n−28n\displaystyle\sum_{n=3}^{\infty} \frac{6^{n-2}}{8^n}n=3∑∞8n6n−2 is
divergent\text{divergent}divergent
27256\displaystyle\frac{27}{256}25627
364\displaystyle\frac{3}{64}643
964\displaystyle\frac{9}{64}649
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