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Differentiability of a Piecewise Function

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Let the function gg be defined by g(x)={x2−2x+1if x<1ex−1−1if x≥1\displaystyle g(x) = \begin{cases} \displaystyle x^2 - 2x + 1 & \text{if } x < 1 \\ \displaystyle e^{x-1} - 1 & \text{if } x \geq 1 \end{cases}. Which of the following statements about gg are true?

I. lim⁡x→1−g(x)=lim⁡x→1+g(x)\displaystyle \lim_{x \to 1^-} g(x) = \lim_{x \to 1^+} g(x)

II. lim⁡x→1−g′(x)=lim⁡x→1+g′(x)\displaystyle \lim_{x \to 1^-} g'(x) = \lim_{x \to 1^+} g'(x)

III. gg is differentiable at x=1x = 1.

A

I only

B

None

C

I and II only

D

III only

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