Finding a Critical Point with Product Rule

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For the function $f(x) = x\sqrt{x+2}$ , what is the value of $x$ for which $f'(x) = 0$ ?

$x = -\frac{2}{3}$

$x = \frac{4}{3}$

$x = -\frac{4}{3}$

$x = 0$

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