The value of limh→0e5+h2−e5h\lim_{h\to0}\frac{e^{5+\frac{h}{2}}-e^{5}}{h}limh→0he5+2h−e5 is
15e5\frac{1}{5}e^{5}51e5
52e5\frac{5}{2}e^{5}25e5
e5e^{5}e5
12e5\frac{1}{2}e^{5}21e5
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AI Tutor 7:52 AM
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