If y=xtanxy = x \tan xy=xtanx, what is the value of dydx\frac{dy}{dx}dxdy at x=π4x = \frac{\pi}{4}x=4π?
π2\displaystyle\frac{\pi}{2}2π
1+π21 + \displaystyle\frac{\pi}{2}1+2π
1+π41 + \displaystyle\frac{\pi}{4}1+4π
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AI Tutor 3:57 AM
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