If f(x)=3x−22x+3f(x) = \frac{3x - 2}{2x + 3}f(x)=2x+33x−2, then f′(x)=f'(x) =f′(x)=
13(2x+3)2\displaystyle\frac{13}{(2x + 3)^2}(2x+3)213
5(2x+3)2\displaystyle\frac{5}{(2x + 3)^2}(2x+3)25
3(2x+3)2\displaystyle\frac{3}{(2x + 3)^2}(2x+3)23
12x+5(2x+3)2\displaystyle\frac{12x + 5}{(2x + 3)^2}(2x+3)212x+5
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