Find the value of x that satisfies the equation 2xx+5−x2x+5−32=0\frac{2x}{\sqrt{x+5}} - \frac{x}{2\sqrt{x+5}} - \frac{3}{2} = 0x+52x−2x+5x−23=0.
x=1+212x = \frac{1+\sqrt{21}}{2}x=21+21
x=1+212x = \sqrt{\frac{1+\sqrt{21}}{2}}x=21+21
x=21−12x = \frac{\sqrt{21}-1}{2}x=221−1
x=1−212x = \frac{1-\sqrt{21}}{2}x=21−21
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AI Tutor 12:39 AM
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