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Solving a Rational Equation with Radicals

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Solve for x: (2∗x+1)3∗x+10−x+10x+2=0.\frac{(2*x+1)}{3*\sqrt{x+10}} - \frac{\sqrt{x+10}}{x+2} = 0.

A

x=14x = \sqrt{14}

B

x=−1+572x = \frac{-1+\sqrt{57}}{2}

C

x=−1+572 and x=−1−572x = \frac{-1+\sqrt{57}}{2}\text{ and }x = \frac{-1-\sqrt{57}}{2}

D

x=−1−572x = \frac{-1-\sqrt{57}}{2}

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