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Derivative of an Inverse Function
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The function $$f$$ is invertible and is defined by $$f(x)=\sqrt{1+x^2}$$. If $$g$$ is the inverse of $$f$$, what is the value of $$g'(\sqrt{2})$$?

The table below shows selected values for $$f$$.

x f(x)
0 1
1 $$\sqrt{2}$$
2 $$\sqrt{5}$$
A

$$\sqrt{2}$$

B

$$2$$

C

$$\frac{1}{\sqrt{2}}$$

D

$$1+\sqrt{2}$$

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