If f(x)=cos(3x2+2)f(x) = \cos(3x^2 + 2)f(x)=cos(3x2+2), then f′(x)=f'(x) =f′(x)=
−6∗sin(3∗x2+2)-6*\sin(3*x^2+2)−6∗sin(3∗x2+2)
−6∗x∗sin(3∗x2+2)-6*x*\sin(3*x^2+2)−6∗x∗sin(3∗x2+2)
−sin(3∗x2+2)-\sin(3*x^2+2)−sin(3∗x2+2)
−6∗x∗cos(3∗x2+2)-6*x*\cos(3*x^2+2)−6∗x∗cos(3∗x2+2)
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AI Tutor 11:50 PM
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