If f(x)=tan−1(3x2)f(x) = \tan^{-1}(3x^2)f(x)=tan−1(3x2), then f′(x)=f'(x) =f′(x)=
3∗x1+9∗x4\frac{3*x}{1+9*x^4}1+9∗x43∗x
6∗x1+3∗x2\frac{6*x}{1+3*x^2}1+3∗x26∗x
6∗x21+9∗x4\frac{6*x^2}{1+9*x^4}1+9∗x46∗x2
6∗x1+9∗x4\frac{6*x}{1+9*x^4}1+9∗x46∗x
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AI Tutor 12:40 AM
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