Derivative of an Inverse Function

Mark

Let $f$ be a one-to-one function defined by $f(x)=e^{x}+x$ . If $g(x)=f^{-1}(x)$ , what is the value of $g'(f(0))$ ?

$1$

$\frac{1}{e^{0}}$

$\frac{1}{2}$

$\frac{1}{e+1}$

Hint

Did You Know?

Explain Why

Explain All Answers

Check Answer

Show Correct Answer

Report Question

Question Leaderboard

Not enough data yet to show leaderboard.

AI Tutor 12:39 AM

How can I help?