Differentiate y=arctan(2∗x−1x+3).y = \arctan\left(\sqrt{\frac{2*x-1}{x+3}}\right).y=arctan(x+32∗x−1).
72∗(x+3)2∗(3∗x+2)∗(2∗x−1x+3)−1/2\frac{7}{2*(x+3)^{2}*(3*x+2)}*\left(\frac{2*x-1}{x+3}\right)^{-1/2}2∗(x+3)2∗(3∗x+2)7∗(x+32∗x−1)−1/2
7∗(x+3)2∗(3∗x+2)∗(2∗x−1x+3)−1/2\frac{7*(x+3)}{2*(3*x+2)}*\left(\frac{2*x-1}{x+3}\right)^{-1/2}2∗(3∗x+2)7∗(x+3)∗(x+32∗x−1)−1/2
72∗(x+3)∗(3∗x+2)∗(2∗x−1x+3)1/2\frac{7}{2*(x+3)*(3*x+2)}*\left(\frac{2*x-1}{x+3}\right)^{1/2}2∗(x+3)∗(3∗x+2)7∗(x+32∗x−1)1/2
72∗(x+3)∗(3∗x+2)∗(2∗x−1x+3)−1/2\frac{7}{2*(x+3)*(3*x+2)}*\left(\frac{2*x-1}{x+3}\right)^{-1/2}2∗(x+3)∗(3∗x+2)7∗(x+32∗x−1)−1/2
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