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Derivative of an Inverse Tangent Function

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Differentiate y=arctan⁡(2∗x−1x+3).y = \arctan\left(\sqrt{\frac{2*x-1}{x+3}}\right).

A

72∗(x+3)2∗(3∗x+2)∗(2∗x−1x+3)−1/2\frac{7}{2*(x+3)^{2}*(3*x+2)}*\left(\frac{2*x-1}{x+3}\right)^{-1/2}

B

7∗(x+3)2∗(3∗x+2)∗(2∗x−1x+3)−1/2\frac{7*(x+3)}{2*(3*x+2)}*\left(\frac{2*x-1}{x+3}\right)^{-1/2}

C

72∗(x+3)∗(3∗x+2)∗(2∗x−1x+3)1/2\frac{7}{2*(x+3)*(3*x+2)}*\left(\frac{2*x-1}{x+3}\right)^{1/2}

D

72∗(x+3)∗(3∗x+2)∗(2∗x−1x+3)−1/2\frac{7}{2*(x+3)*(3*x+2)}*\left(\frac{2*x-1}{x+3}\right)^{-1/2}

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