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Derivatives of Inverse Secant and Tangent

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Which statement best describes how the domain of sec⁡−1(x)\sec^{-1}(x) influences its derivative in comparison to the derivative of tan⁡−1(x)\tan^{-1}(x)?

A

The domain of sec⁡−1(x)\sec^{-1}(x) leads to a simpler derivative without absolute value, unlike the more complex derivative of tan⁡−1(x)\tan^{-1}(x).

B

Both sec⁡−1(x)\sec^{-1}(x) and tan⁡−1(x)\tan^{-1}(x) have identical domains, resulting in derivatives with the same level of complexity and form.

C

The domain of sec⁡−1(x)\sec^{-1}(x) (∣x∣≥1|x| \geq 1) results in a more complex derivative with ∣x∣|x|, while tan⁡−1(x)\tan^{-1}(x)’s domain allows for a simpler form.

D

The domain of sec⁡−1(x)\sec^{-1}(x) causes its derivative to be undefined for all real numbers, while tan⁡−1(x)\tan^{-1}(x)’s derivative is defined everywhere.

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