Higher-Order Derivative Evaluation
Let the function h be defined by h(t) = ln(t²+1). If h''(0) = k, then h^(4)(0) =
A
24
B
-24
C
6k
D
-6k
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Let the function h be defined by h(t) = ln(t²+1). If h''(0) = k, then h^(4)(0) =
24
-24
6k
-6k
Not enough data yet to show leaderboard.