Given ex∗y+x2−y2=1,e^{x*y}+x^{2}-y^{2}=1,ex∗y+x2−y2=1, find dydx.\frac{dy}{dx}.dxdy.
dydx=−ex∗y∗y−2∗xex∗y∗x+2∗y\frac{dy}{dx}=\frac{-e^{x*y}*y-2*x}{e^{x*y}*x+2*y}dxdy=ex∗y∗x+2∗y−ex∗y∗y−2∗x
dydx=−ex∗y∗y−2∗xex∗y∗x−2∗y\frac{dy}{dx}=\frac{-e^{x*y}*y-2*x}{e^{x*y}*x-2*y}dxdy=ex∗y∗x−2∗y−ex∗y∗y−2∗x
dydx=ex∗y∗y+2∗xex∗y∗x−2∗y\frac{dy}{dx}=\frac{e^{x*y}*y+2*x}{e^{x*y}*x-2*y}dxdy=ex∗y∗x−2∗yex∗y∗y+2∗x
dydx=−ex∗y∗y+2∗xex∗y∗x−2∗y\frac{dy}{dx}=\frac{-e^{x*y}*y+2*x}{e^{x*y}*x-2*y}dxdy=ex∗y∗x−2∗y−ex∗y∗y+2∗x
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AI Tutor 3:09 AM
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