If y=(cos(3∗x))3y = (\cos(3*x))^{3}y=(cos(3∗x))3, what is d2ydx2\frac{d^2y}{dx^2}dx2d2y?
54∗cos(3∗x)∗sin(3∗x)2−27∗cos(3∗x)354*\cos(3*x)*\sin(3*x)^{2}-27*\cos(3*x)^{3}54∗cos(3∗x)∗sin(3∗x)2−27∗cos(3∗x)3
−54∗cos(3∗x)∗sin(3∗x)2+27∗cos(3∗x)3-54*\cos(3*x)*\sin(3*x)^{2}+27*\cos(3*x)^{3}−54∗cos(3∗x)∗sin(3∗x)2+27∗cos(3∗x)3
54∗cos(3∗x)∗sin(3∗x)−27∗cos(3∗x)354*\cos(3*x)*\sin(3*x)-27*\cos(3*x)^{3}54∗cos(3∗x)∗sin(3∗x)−27∗cos(3∗x)3
54∗cos(3∗x)∗sin(3∗x)2−27∗cos(3∗x)3+3∗sin(3∗x)54*\cos(3*x)*\sin(3*x)^{2}-27*\cos(3*x)^{3}+3*\sin(3*x)54∗cos(3∗x)∗sin(3∗x)2−27∗cos(3∗x)3+3∗sin(3∗x)
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AI Tutor 2:22 AM
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