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Solving a Radical Equation in Quadratic Form
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Solve for x in the equation

$$\sqrt{x+7}+\frac{2}{\sqrt{x+7}}=5.$$

(Use the substitution $$u=\sqrt{x+7}$$ and then solve for x.)

u = √(x+7) Equation Form
u u + 2/u = 5
Leads to: u² - 5u + 2 = 0
A

$$\left(\frac{5\pm\sqrt{17}}{2}\right)^2-7$$

B

$$\frac{5+\sqrt{17}}{2}-7$$

C

$$7-\left(\frac{5\pm\sqrt{17}}{2}\right)^2$$

D

$$\left(\frac{5-\sqrt{17}}{2}\right)^2-7$$

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