L'Hôpital's Rule for Limits at Infinity
Using L’Hôpital’s Rule, what is the value of $$\lim_{x \to \infty}\frac{5x^3 - 4x^2 + 1}{7x^3 + 2x - 6}$$?
A
$$\frac{5}{3}$$
B
$$\frac{1}{7}$$
C
$$0$$
D
$$\frac{5}{7}$$
Question Leaderboard
Not enough data yet to show leaderboard.