Critical Numbers of a Rational Function
Which of the following statements is true about the critical numbers of the function $$f$$ defined by $$f(x)=\frac{x}{x+1}$$?
A
There are infinitely many critical numbers because the derivative is a constant positive value, indicating no change in the behavior of $$f(x)$$.
B
Critical numbers occur where the derivative is undefined; hence, $$x=-1$$ is the unique critical number of $$f(x)$$.
C
The function has no critical numbers because its derivative $$f'(x)=\frac{1}{(x+1)^2}$$ is always positive for $$x\neq -1$$, and $$x=-1$$ is not in the domain.
D
The only critical number is $$x=-1$$, where the derivative is zero.
Question Leaderboard
| Rank | |||||
|---|---|---|---|---|---|
| #1 | alexaserrano2008 | 2 | 3 | 1m 06s | 124 |
| #2 | berraoner2009 | 1 | 1 | 1m 58s | -18 |
| #3 | richa.tuli | 0 | 1 | 0m 15s | -25 |
| #4 | yeejayc | 1 | 2 | 2m 11s | -41 |
| #5 | alexyu2008 | 0 | 1 | 0m 57s | -67 |
| #6 | sgarv2513 | 1 | 2 | 3m 43s | -133 |
| #7 | suhanakochhar006 | 0 | 1 | 2m 19s | -149 |
Items per page:
10
1 – 7 of 7
APFIVE