Absolute Extrema On A Closed Interval

Question

A company’s profit is modeled by the quadratic function $$f(x)= -x^2+4*x+5$$ over the interval $$[0,5]$$. Use the Extreme Value Theorem to determine the absolute maximum and minimum values of the profit on this interval.
 
| x | f(x)= -x^2+4*x+5 |
|---|-----------------|
| 0 | 5               |
| 2 | 9               |
| 5 | 0               |

Accepted Answer

Absolute maximum: $$9$$ at $$x=2$$; Absolute minimum: $$0$$ at $$x=5$$.

Answer

Absolute maximum: $$5$$ at $$x=0$$; Absolute minimum: $$0$$ at $$x=5$$.

Answer

Absolute maximum: $$0$$ at $$x=5$$; Absolute minimum: $$9$$ at $$x=2$$.

Answer

Absolute maximum: $$9$$ at $$x=2$$; Absolute minimum: $$5$$ at $$x=0$$.

Rank	User	Correct Count	Attempt Count	Total Time	Score
#1	suhanakochhar006	1	1	1m 31s	9
#2	berraoner2009	1	1	2m 18s	-38
#3	richa.tuli	1	1	3m 11s	-91
#4	yeejayc	1	3	3m 31s	-131

Absolute Extrema On A Closed Interval

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