Absolute Minimum on a Closed Interval

Question

The graph above represents the function $$h(x)=\frac{1}{x^2+1}$$ on the interval $$[-2, 2]$$. Determine the absolute minimum value of $$h(x)$$ on this interval.

Accepted Answer

Absolute minimum value is $$\frac{1}{5}$$

Answer

Absolute minimum value is $$1$$

Answer

Absolute minimum value is $$\frac{1}{2}$$

Answer

The function does not have an absolute minimum

Rank	User	Correct Count	Attempt Count	Total Time	Score
#1	richa.tuli	1	1	1m 25s	15
#2	haneesh19.12	0	1	0m 00s	-10
#3	berraoner2009	0	2	3m 16s	-216
#4	yeejayc	1	1	8m 22s	-402

Absolute Minimum on a Closed Interval

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