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Applying the Mean Value Theorem

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In the context of the Mean Value Theorem, let f(x)=x2+9−1x+2f(x)=\sqrt{x^2+9}-\frac{1}{x+2} on the closed interval [1,4][1,4]. The theorem guarantees that there exists a number c in (1,4) such that

f′(c)=f(4)−f(1)4−1.f'(c)=\frac{f(4)-f(1)}{4-1}.

Solve the equation f′(c)=f(4)−f(1)3f'(c)=\frac{f(4)-f(1)}{3} to determine, approximately, the value of c.

A

Approximately 1.85

B

Approximately 2.33

C

Approximately 3.05

D

Approximately 2.78

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