Derivative of an Inverse Function

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Let $f(x)=x^3+3x^2-4x+8$ . If $g$ is the inverse function of $f$ and $g(8)=1$ , what is the value of $g'(8)$ ?

$\frac{1}{8}$

$\frac{1}{5}$

$\frac{1}{7}$

$\frac{1}{6}$

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