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Implicit Differentiation

Mark

If $y$ is a function of $x$ such that $y^3 + y = x^2$ , then $\displaystyle \frac{dy}{dx} =$

A

$\displaystyle \frac{2x}{1 + 3y^2}$

B

$0$

C

$\displaystyle \frac{2x}{3y^2}$

D

$\displaystyle \frac{x}{2}$

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