If ex2+y−xy=ee^{x^2 + y} - xy = eex2+y−xy=e, then at x=1x=1x=1 and y=0y=0y=0, dydx=\frac{dy}{dx}=dxdy=
−2ee−1\frac{-2e}{e-1}e−1−2e
2ee−1\frac{2e}{e-1}e−12e
−2ee+1\frac{-2e}{e+1}e+1−2e
2e1+e\frac{2e}{1+e}1+e2e
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AI Tutor 10:10 AM
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