Evaluate the integral: ∫3x+1x2−4x+3 dx\displaystyle \int \frac{3x + 1}{x^2 - 4x + 3} \, dx∫x2−4x+33x+1dx
−2ln∣x−3∣+5ln∣x−1∣+C\displaystyle -2 \ln|x - 3| + 5 \ln|x - 1| + C−2ln∣x−3∣+5ln∣x−1∣+C
15ln∣x−3∣−12ln∣x−1∣+C\displaystyle \frac{1}{5} \ln|x - 3| - \frac{1}{2} \ln|x - 1| + C51ln∣x−3∣−21ln∣x−1∣+C
12ln∣x−3∣−12ln∣x−1∣+C\displaystyle \frac{1}{2} \ln|x - 3| - \frac{1}{2} \ln|x - 1| + C21ln∣x−3∣−21ln∣x−1∣+C
5ln∣x−3∣−2ln∣x−1∣+C\displaystyle 5 \ln|x - 3| - 2 \ln|x - 1| + C5ln∣x−3∣−2ln∣x−1∣+C
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