L'Hôpital's Rule with an Exponential Function

Question

Which of the following statements is true about the limit $$\lim_{x	o 0} \frac{e^{2x}-1}{x}$$?

Accepted Answer

The limit equals 2, since applying L'Hôpital's Rule yields $$\frac{2*e^{2*x}}{1}$$ evaluated at x = 0.

Answer

The limit equals $$e^2$$, as the exponential function dominates near x = 0.

Answer

The limit does not exist because the numerator and denominator both approach 0.

Answer

The limit equals 1, by directly substituting x = 0 into the exponential function.

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