If y=(x3−2x+1)6x+2y = (x^3 - 2x + 1)\sqrt{6x + 2}y=(x3−2x+1)6x+2, then y′=y' = y′=
3x3−6x+36x+2\displaystyle\frac{3x^3 - 6x + 3}{\sqrt{6x + 2}}6x+23x3−6x+3
21x3+6x2−18x−16x+2\displaystyle\frac{21x^3 + 6x^2 - 18x - 1}{\sqrt{6x + 2}}6x+221x3+6x2−18x−1
18x3−12x+66x+2\displaystyle\frac{18x^3 - 12x + 6}{\sqrt{6x + 2}}6x+218x3−12x+6
(3x2−2)6x+2(3x^2 - 2)\sqrt{6x + 2}(3x2−2)6x+2
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AI Tutor 3:10 AM
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