Solve the equation sin(2∗x)=0\sin(2*x)=0sin(2∗x)=0 for xxx in the interval [0,π][0,\pi][0,π].
x=π2x=\frac{\pi}{2}x=2π
x=0,π2,πx=0,\frac{\pi}{2},\pix=0,2π,π
x=0,π3,2π3,πx=0,\frac{\pi}{3},\frac{2\pi}{3},\pix=0,3π,32π,π
x=0,πx=0,\pix=0,π
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AI Tutor 6:03 AM
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