Evaluate ∫x3−2x2+4x−8x2(x−2)2 dx\int \frac{x^3 - 2x^2 + 4x - 8}{x^2 (x-2)^2}\; dx∫x2(x−2)2x3−2x2+4x−8dx.
−ln∣x∣+2x+2ln∣x−2∣+C-\ln|x| + \frac{2}{x} + 2\ln|x-2| + C−ln∣x∣+x2+2ln∣x−2∣+C
ln∣x/(x−2)∣−1/x+2/(x−2)+Cln|x/(x-2)| - 1/x + 2/(x-2) + Cln∣x/(x−2)∣−1/x+2/(x−2)+C
ln∣x∣−ln∣x−2∣−1/x+2/(x−2)+Cln|x| - ln|x-2| - 1/x + 2/(x-2) + Cln∣x∣−ln∣x−2∣−1/x+2/(x−2)+C
ln∣x∣+ln∣x−2∣−1/x−2/(x−2)+Cln|x| + ln|x-2| - 1/x - 2/(x-2) + Cln∣x∣+ln∣x−2∣−1/x−2/(x−2)+C
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AI Tutor 5:04 AM
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