∫x2+x+3x2−4 dx=\displaystyle \int \frac{x^2 + x + 3}{x^2 - 4} \, dx = ∫x2−4x2+x+3dx=
x+94ln∣x−2∣−54ln∣x+2∣+C\displaystyle x + \frac{9}{4} \ln |x - 2| - \frac{5}{4} \ln |x + 2| + Cx+49ln∣x−2∣−45ln∣x+2∣+C
94ln∣x−2∣−54ln∣x+2∣+C\displaystyle \frac{9}{4} \ln |x - 2| - \frac{5}{4} \ln |x + 2| + C49ln∣x−2∣−45ln∣x+2∣+C
x−94ln∣x−2∣+54ln∣x+2∣+C\displaystyle x - \frac{9}{4} \ln |x - 2| + \frac{5}{4} \ln |x + 2| + Cx−49ln∣x−2∣+45ln∣x+2∣+C
x+54ln∣x−2∣−94ln∣x+2∣+C\displaystyle x + \frac{5}{4} \ln |x - 2| - \frac{9}{4} \ln |x + 2| + Cx+45ln∣x−2∣−49ln∣x+2∣+C
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