Logarithmic Integration Rule

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Evaluate $\displaystyle\int_1^e \frac{2x + 3}{x^2 + 3x} \, dx$

$2e + 3 - \ln(e + 3)$

$e^2 + 3e - 4$

$\frac{e^2 + 3e}{4}$

$\ln(e^2 + 3e) - \ln 4$

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