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AP Calculus BC/Unit 7: Differential Equations
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Solving An Initial Value Problem
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All of the following statements about solving the initial value problem $$\frac{dy}{dx} = 4x$$ with the initial condition $$y(1) = 3$$ are correct EXCEPT:

A

Integrating $$4*x$$ gives $$y = 2*x^2 + C$$, then using $$y(1) = 3$$ to solve for $$C$$.

B

The antiderivative of $$4*x$$ is $$2*x^2$$ because $$\frac{d}{dx}(2*x^2) = 4*x$$.

C

After determining $$C$$, the particular solution represents a parabola passing through $$(1, 3)$$.

D

Integrating $$4*x$$ directly gives $$y = 4*x + C$$.

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