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AP Calculus BC/Unit 7: Differential Equations
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Particular Solution to a Differential Equation
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What is the particular solution to the differential equation $$ \frac{dy}{dx} = \frac{4y}{2x - 3} $$ with the initial condition $$ y(2) = \frac{1}{2} $$ for $$ x > \frac{3}{2} $$?

A

$$ y = \frac{1}{2}e^{4x - 6} $$

B

$$ y = \frac{1}{2}\ln(2x - 3) + \frac{1}{2} $$

C

$$ y = 2x - 2 $$

D

$$ y = \frac{1}{2}(2x - 3)^2 $$

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