Particular Solution as a Definite Integral
Let $$y=r(x)$$ be the particular solution to the differential equation $$\frac{dy}{dx}=\frac{1}{\sqrt{1+x^4}}$$ with the initial condition $$r(2)=5$$. Which of the following defines $$r(x)$$?
A
$$r(x)=5+\int_2^x\frac{1}{\sqrt{1+t^4}}\, dt$$
B
$$r(x)=5+\int_0^2\frac{1}{\sqrt{1+t^4}}\, dt$$
C
$$r(x)=\frac{-2x^3}{(1+x^4)^{3/2}}$$
D
$$r(x)=\arctan(x^2)+C$$
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