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AP Calculus BC/Unit 7: Differential Equations
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Particular Solution as a Definite Integral
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Let $$y=r(x)$$ be the particular solution to the differential equation $$\frac{dy}{dx}=\frac{1}{\sqrt{1+x^4}}$$ with the initial condition $$r(2)=5$$. Which of the following defines $$r(x)$$?

A

$$r(x)=5+\int_2^x\frac{1}{\sqrt{1+t^4}}\, dt$$

B

$$r(x)=5+\int_0^2\frac{1}{\sqrt{1+t^4}}\, dt$$

C

$$r(x)=\frac{-2x^3}{(1+x^4)^{3/2}}$$

D

$$r(x)=\arctan(x^2)+C$$

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