Particular Solution to a Differential Equation
If $$\displaystyle\frac{dy}{dx} = y^2$$ and $$y = \frac{1}{2}$$ when $$x = 0$$, then $$y =$$
A
$$\frac{1}{x-2}$$
B
$$\frac{1}{2+x}$$
C
$$\frac{1}{2-x}$$
D
$$\frac{2}{2-x}$$
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