Particular Solution as an Integral

Question

Let $$y=z(x)$$ be the particular solution to the differential equation $$\frac{dy}{dx}=xe^{x^2}$$ with the initial condition $$z(0)=-2$$. Which of the following is true?

Accepted Answer

$$z(x)=-2+\int_0^xte^{t^2}\, dt$$

Answer

$$z(x)=-2+\int_1^xte^{t^2}\, dt$$

Answer

$$z(x)=(2x+1)e^{x^2}$$

Answer

$$z(x)=\frac{1}{2}e^{x^2}$$

Particular Solution as an Integral

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