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AP Calculus BC/Unit 7: Differential Equations
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easy

Separation of Variables Initial Value Problem

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Which of the following is the solution to the differential equation dydx=yex \frac{dy}{dx} = ye^x with the initial condition y(0)=3 y(0) = 3 ?

A

y=3ex22 y = 3e^{\frac{x^2}{2}}

B

y=3eex−1 y = 3e^{e^x - 1}

C

y=3ln⁡(ex)+3 y = 3\ln(e^x) + 3

D

y=3ex+3 y = 3e^x + 3

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