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AP Calculus BC/Unit 7: Differential Equations
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Solving a Separable Differential Equation

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What is the solution to the differential equation dydx=5y2\displaystyle \frac{dy}{dx} = 5y^2 satisfying the initial condition y(0)=3y(0) = 3?

A

y=e5x+9y = \sqrt{e^{5x} + 9}

B

y=9e5xy = \sqrt{9e^{5x}}

C

y=3115xy = \displaystyle \frac{3}{1-15x}

D

y=19e5xy = \sqrt{\displaystyle \frac{1}{9}e^{5x}}

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#1p25000115522 0m 00s 200
#2haneesh19.1202 0m 00s -20
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