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AP Calculus BC/Unit 7: Differential Equations
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Solving a Separable Differential Equation

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Which of the following is the solution to the differential equation dydx=yx+1\displaystyle\frac{dy}{dx} = \displaystyle\frac{y}{x+1} with the initial condition y(0)=4y(0) = 4?

A

y=4x+1\displaystyle y = \frac{4}{x+1}

B

y=4(x+1)\displaystyle y = 4(x+1)

C

y=4ln⁡(x+1)+4\displaystyle y = 4\ln(x+1) + 4

D

y=4ex+1\displaystyle y = 4e^{x+1}

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