Solving an Initial Value Problem

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Let $y(t)$ be the solution to the differential equation $\displaystyle \frac{dy}{dt} = -10e^{-t/2}$ with the initial condition $y(0) = 20$ . What is the value of $y(6)$ ?

$20e^{-2}$

$20e^{-6}$

$20e^{-3}$

$10e^{-3}$

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