Particle Position From Velocity

Question

A particle moves along the $$x$$-axis so that its velocity at time $$t$$ is given by $$v(t) = \displaystyle\frac{3t}{t^2 + 1}$$. At time $$t = 0$$, the position of the particle is $$x = 0$$. What is the position of the particle at time $$t = 2$$?

Accepted Answer

$$\displaystyle\frac{3}{2}\ln(5)$$

Answer

$$3\ln(5)$$

Answer

$$\displaystyle\frac{3}{2}\ln(4)$$

Answer

$$\displaystyle\frac{3}{2}\ln(3)$$

Particle Position From Velocity

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