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AP Calculus BC/Unit 8: Applications of Integration
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Properties Of The Average Value Of A Function

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Let ff be a function that is continuous on the interval [0,10][0, 10]. All of the following statements are true EXCEPT:

A

The average value of f(x)f(x) on [0,10] is necessarily attained at x=5x=5, the midpoint of the interval.

B

According to the Mean Value Theorem for Integrals, there exists some c∈[0,10]c \in [0,10] such that f(c)f(c) equals the average value of f(x)f(x) on [0,10].

C

Critical points, where f′(x)=0f'(x)=0, are not required to coincide with the point where f(x)f(x) equals its average value on [0,10].

D

The average value is computed as 110∫010f(x) dx\frac{1}{10}\int_{0}^{10} f(x)\,dx.

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